Photoelectric Effect: A Na vapor light emits 10W of light energy. Its wavelenght = 539nm and spreads in all directions. How many photons pass through your pupil (diameter 4mm) in 1s if you stand 10m away?
Okay, my initial approach was to find the total number of photons emitted per second by dividing the power (10 J/s) by the energy per photon (J/photon = hf = hc/lambda). I then took this number and multiplied it by \[(.002^2*pi)/10^2\] thinking that the area of the target is 4mm and the intensity of the light would drop off by r^2. This approach however was wrong according to my professor.
He suggested I look up "solid angles" and work from there. My understanding of this advice is that the eye can be modeled as having a solid angle, theta, and the area the eye sees would be related to the following drawing|dw:1412347332925:dw|
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