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OpenStudy (bossimbacon):
How many solutions does the equation have?
2(2x+5)=4(x+3)
A.
one solution
B.
infinite solutions
C.
no solution
@cj49
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OpenStudy (bossimbacon):
@Haseeb96
OpenStudy (cwrw238):
2(2x+5)=4(x+3)
4x + 20 = 4x + 12
subtract 4x from both sides
20 = 12
No solution
OpenStudy (haseeb96):
It has no solution
OpenStudy (cj49):
^
OpenStudy (bossimbacon):
thanks can i ask doe more?
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OpenStudy (cwrw238):
* should be 4x + 10
10 = 12
still no solution
OpenStudy (bossimbacon):
How many solutions does the equation have?
a+5=1/5(5a+25)
A.
one solution
B.
infinite solutions
C.
no solution
OpenStudy (cwrw238):
a+5=1/5(5a+25)
a + 5 = a + 5
you can assign any value you like to a
so infinite solutions
OpenStudy (bossimbacon):
thanks^ one few more?
OpenStudy (bossimbacon):
How many solutions does the equation have?
3(4x-3)-7x=5x-9
A.
one solution
B.
infinite solutions
C.
no solution
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OpenStudy (cwrw238):
can you try this yourself?
first distribute the 3 over the parentheses;
12x - 9 - 7x = 5x - 9
can you continue?
OpenStudy (cwrw238):
work out 12x - 7x = ?
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