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Discrete Math
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Prove [(p∧q) → r] → [(p→r)⋁(q→r)] is a tautology without using a truth table.
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what other method do you use other than truth table?
I am not sure. I think we are supposed to use logical equivalences.. Demorgan laws, implication law, etc
thats why I am asking for help on here
hello?
left side:\[=\neg r \to\neg ( p \wedge q)\]\[=\neg r \to (\neg p \vee \neg q)\] right side:\[= \left( \neg r \to \neg p \right) \vee \left( \neg r \to \neg q \right)\]
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just using implication and deMorgan
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