Question

5. The discriminant of a quadratic equation is 5. Which describes the number and type of solutions of the equation?
I think its 2 complex solutions

Answer 1

no its 2 solutions but they are both rel numbers

Answer 2

they would be complex if discriminant was negative 5

Answer 3

if you mean 2 real solutions your wrong Im redoing my test and I got that to but it was wrong

Answer 4

The discriminant of a quadratic equation is 5. Which describes the number and type of solutions of the equation?

Answer 5

there are 2 solutions - do you agree with that?

Answer 6

no t didnt say there are 2 real and 2 complex.
the answer is definitely 2 real solutions

Answer 7

Solve x^2 + x + 5 = 0 using the Quadratic Formula. What is the solution set? okay I'll put that one can you help me with this one plz

Answer 8

x = [-1 +/- sqrt(1^2 - 4*1*5)] / 2

Answer 9

note the discriminant here : - its 1 - 20 = -19
- here we have 2 complex number roots

Answer 10

ok I got 1\[\left\{ 1\pm i/2 \right\}\]

Answer 11

x = -1 +i sqrt19 -1 - i sqrt19
---------- , ------------
2 2

Answer 12

how did you got sqrt of 19? Im confuse

Answer 13

the discriminant is b^2 - 4ac for the equation ax^2 + bx + c = 0

compare this with your equation : b = 1, a = 1 and c = 5

so b^2 - 4ac = 1^2 - 4*1*5 = 1 - 20 = -19

Answer 14

on the first question it was 2 complex solutions for -5 you were not correct and on the second one you were correct and thank you!

Answer 15

sqrt (-19) = sqrt( -1 * 19) = i sqrt19

Answer 16

yw