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Mathematics 21 Online
OpenStudy (anonymous):

Find the limit

OpenStudy (anonymous):

\[\lim_{x \rightarrow 2}\frac{ \sin(2(x-2)) }{ x-2 }\]

OpenStudy (anonymous):

I know it's 2. How do I show that using the defintion that lim x->- of sin(x)/x is 1?

OpenStudy (anonymous):

Sorry How do I show that using the definition that lim x->0 of sin(x)/x is 1?

OpenStudy (anonymous):

Nvm. I think I got it.

OpenStudy (baldymcgee6):

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