Evaluate 24-x when x=6. Write the answer as a decimal. Round to the nearest hundredth if necessary. how would you solve that?
plugin x = 6 and simplify
\[\large 24-6\]
so i subtract that 24-6
Exactly!
but how did you get 24
the name of this lesson i am in is Rationals, Irrationals, and Radicals
Okay, could you take a screenshot of the question and attach if psble ?
how do you take a screen shot on a PC
http://www.techcreak.com/wp-content/uploads/2014/09/prtsc-take-screen-shot.jpg
press that, then open paint and paste it
i press what it told me but nothing happened
or use the draw feature ....
\[\sqrt{24-x} when x=6 \]
Write the answer as a decimal. Round to the nearest hundredth if necessary.
Oh so you have that radical in the original expression
still the process is same - simply plug in x = 6 and evaluate
\[\large \sqrt{24-6}\]
A. 1.41 B. 3 C.4.24 D. 9
these are what i have to choose from A. 1.41 B. 3 C.4.24 D. 9
which 2 perfect squares does this come between?
as in
as in, the squart root of 24-6 falls between which 2 perfect squares
i have to subtract right and if i do that it gives me 18
good now 18 isnt a perfect square, its an integer whose square root is not an integer but it falls between 2 perfect squares can you make a small list of perfect suqares?
so 24-6 has two perfect square to let you know i need an example i am not that great with math but an example will help me
24-6 = 18 and we want to know where 18 fits in a list of perfect squares ... 1^2 = 1 2^2 = 4 3^2 = 9 4^2 = 16 (**)^2 = 18 <------ 5^2 = 25
18 fits between 16 and 25, so the sqrt(18) fits between 4 and 5
only one of your options is bigger than 4, but less than 5
9 is bigger and 3 is less
so we know the answer aint 9 or 3
1.41 is less 4.29 is between 5
so we should go with 4.29, do you agree?
i agree cus it's less then 5 but at the same time it's not larger then 5 thank very much
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