If the area of triangle DEF is 220.5 cm^2, what is the area of triangle ABC?
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ABC~DEF
from the triangle DEF you know its area and base then you can find the height
h=2*220.5/21 =441/21 =21
yes but no need
for two similiar triangles, ratio of areas = ratio of sides squared
25/49?
You there @caozeyuan
@MaryLovell15 Still need help with it?
Yes! :( @JonnyVonny
Mmk, so, you found the height of one triangle, and you know its base.
Right.
So, the height and base are both 21?...
Yup, which, some triangles are like that. They are called equilateral triangles; the sides and angles are all the same.
So, you have the height and base, and you know they're similar, so you can set up a ratio between the two:
height 21 x height base 21 15 height
Are you following me? Or are you confused?
I understand so far.
So, now that we have those ratios, we can cross multiply and solve for x. Tell me what you get and I'll tell you what I got.
x=15
@JonnyVonny
Yes, that is what i got aswell
So the area is 112.5?
So, now, just get the area via: A=.5b*h
Yup, well, thats what we both got, at least.
There shouldn't be a reason why its wrong. Math does have a way at getting at you, however.:b
I honestly don't care if it's wrong at this point. Lol, I've been stuck on this for awhile.
Lol, I was just playing around; this is the way you're suppose to do it; find comparable numbers, then cross multiply. Know this process; you'll be using it a lot.
Thanks for your help!
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