Can someone show me thoroughl steps on how tthis should be done please.
An athlete executing a long jump leaves the ground at 28.0 angle and travels 7.80 m a)What was the take off speed? b)If this speed were increased by just 5.0%,how much longer would the jump be?

Question

Can someone show me thoroughl steps on how tthis should be done please. 
An athlete executing a long jump leaves the ground at 28.0 angle and travels 7.80 m a)What was the take off speed? b)If this speed were increased by just 5.0%,how much longer would the jump be?

anonymous · Answer

@pkjag

anonymous · Answer

(a) Use $$v^{2}=u^{2}\sin^{2}\theta-2gs$$ we know that $$v=0$$ at maximum height, if we take 7.8m to be the vertical height $$s$$, then substitute for $$\theta$$ and $$s$$  and find the take off speed $$u$$
(b) Use the same equation here, just increase the answer you got from (a) by 5%, which should be $$u \times \frac{105}{100}$$ then substitute that in our equation and solve for $$s$$, then subtract 7.8 from your answer.

anonymous · Answer

for the 1st equation is it the same as vx=vox?

anonymous · Answer

it doesn't matter either way $$v=0$$

anonymous · Answer

ok thanks