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Chemistry 19 Online
OpenStudy (anonymous):

determine the resulting ionic formula and names for the following pairs of cations/anions: a.) Potassium/Bromine b.) Iron (II)/Chlorine c.) Magnesium/Carbonate

OpenStudy (paxpolaris):

\[K^+ + Br^- \to KBr\]\[Fe^{2+}+ 2 Cl^- \to FeCl_2\]

OpenStudy (anonymous):

so how many cations/anions for the first one?

OpenStudy (paxpolaris):

\[Mg^{2+}+{CO_3}^{2-}= MgCO_3\]

OpenStudy (paxpolaris):

since Potassium has +1 charge and Bromide has -1 ... they combine in 1:1 ratio

OpenStudy (anonymous):

so 1 cation and 1 anion

OpenStudy (paxpolaris):

right

OpenStudy (anonymous):

so b.) has 2 anions and 1 cation correct.

OpenStudy (anonymous):

and c.) (magnesium/carbonate) has 2 cations and 2 anions?

OpenStudy (paxpolaris):

c ) 2:2 is the same as 1: 1

OpenStudy (anonymous):

so it has 1 anion and 1 cation?

OpenStudy (paxpolaris):

right

OpenStudy (anonymous):

and what about b?

OpenStudy (paxpolaris):

b is correct

OpenStudy (anonymous):

so b has 2 anions and 1 cation...just making extra sure haha

OpenStudy (paxpolaris):

yes

OpenStudy (paxpolaris):

Iron(II) has +2 charge, chloride has -1 .... so to balance the charges Ferrous Chloride will have twice as many anions to cations

OpenStudy (anonymous):

perfect that makes sense...thank you!!

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