evaluate without a calculator:
logbase3(5) x logbase5(27)

i changed it to 1/[logbase5(3)] x logbase5(27)
then i got stuck D:

Question

evaluate without a calculator:
logbase3(5) x logbase5(27)

i changed it to 1/[logbase5(3)] x logbase5(27)
then i got stuck D:

paxpolaris · Answer

it's multiplication not plus, huh?

anonymous · Answer

yup D:

paxpolaris · Answer

$$\log_3(5) \times \log_5 (27)$$$$={1 \over \log_5(3)} \times \log_5(27)$$

paxpolaris · Answer

27 = 3^3

anonymous · Answer

how did you change 1/logbase5(3) to 3^3?

jim_thompson5910 · Answer

PaxPolaris is saying 27 is equal to 3^3

not 1/logbase5(3)

anonymous · Answer

oh yeah right oops
so 1/logbase5(3) x logbase5(3^3)
i don't see how i can find that D:

jim_thompson5910 · Answer

what can you do with $$\Large \log_{5}(3^3)$$

jim_thompson5910 · Answer

look at your notes for the log rules

anonymous · Answer

oh.. 1? 

so it becomes 1/logbase5(3)
=logbase3(5)
=?

jim_thompson5910 · Answer

nope

jim_thompson5910 · Answer

what can you do with that exponent?

anonymous · Answer

logbase5(3^3) is 1 isn't it

paxpolaris · Answer

$$\Large \log \left( a^b \right)=b \cdot \log \left( a \right)$$

jim_thompson5910 · Answer

yes, so $$\Large \log_{5}(3^3) = ??$$

anonymous · Answer

oh okay 3logbase5(3) x 1/logbase5(3)

jim_thompson5910 · Answer

and then you can say

$$\Large \frac{3*\log_{5}(3)}{\log_{5}(3)}$$

jim_thompson5910 · Answer

after you've multiplied the terms

anonymous · Answer

ah 3

thank you ^^

jim_thompson5910 · Answer

yep