Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Got a calculus question i need some help with

OpenStudy (anonymous):

OpenStudy (anonymous):

here is it, so far i got.. \[g(x) = 55\] \[f(g) = f(55) = 10\]

OpenStudy (anonymous):

where do i go from here? i think im supposed to find the slope of the lines?

OpenStudy (tkhunny):

You will need the Chain Rule, I think. \(\dfrac{d}{dx}f(g(x)) = f'(g(x))\cdot g'(x)\). That should be easier.

OpenStudy (anonymous):

hmm alright let me take a look with that in mind

OpenStudy (anonymous):

so i do need to find the slope of the lines correct?

OpenStudy (anonymous):

ooh im doing #55 btw

OpenStudy (tkhunny):

Right. You should be able to calculate the slope from the appearance of the graph.

OpenStudy (anonymous):

slope for left graph: 1/4 slope for right graph: -1/2 sound right to you?

OpenStudy (anonymous):

actually switch that around

OpenStudy (anonymous):

left -1/2 and right 1/4

OpenStudy (tkhunny):

There are 4 slopes - two for each graph. Make sure you know where you hit it.

OpenStudy (anonymous):

oh goodness, 2 ea? my teacher definitely never told us that

OpenStudy (anonymous):

ok so slopes are: f(x): -2 and 1 g(x): 1/2 and 0

OpenStudy (anonymous):

@tkhunny mind checking these? and helping me figure the next step?

OpenStudy (tkhunny):

Notation Check: f'(x): -2 and 1 g'(x): 1/2 and 0 Now, go get 'em. gtg sorry.

OpenStudy (anonymous):

@ganeshie8 hey any chance youd have some time to help me work this problem? i mean other people tried but i just dont understand what im really supposed to be doing..

ganeshie8 (ganeshie8):

f(x) has two lines : |dw:1412571965911:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!