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Using natural log, solve for x. 2^x-4 = 5.
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Can someone please show me the steps
Is it \(\large 2^{x-4} = 5\) ?
yes
\[ \large 2^{x-4} = 5 \\ \text{ } \\ \text{Take the natural logarithm on both sides: } \\ \text{ } \\ \ln(2^{x-4}) = \ln(5) \\ \large (x-4)\ln(2) = \ln(5) \\ x - 4 = \frac{\ln(5)}{\ln(2)} \\ x = 4 + \frac{\ln(5)}{\ln(2)} \]
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