Question

find asymptotes of f(x) = (x+1)/(x^2+x)

Answer 1

@danish071996 @ganeshie8

Answer 2

factor denominator and see if anything cancels out

Answer 3

x=0

Answer 4

so is there a hole at x=-1

Answer 5

and what are the horizontal and vertical asymptotes

Answer 6

you're right, x = -1 is just a hole cuz the factor (x+1) cancels out

Answer 7

the only realy vertical asymptote is x=0

Answer 8

do you know the process to find horizontal asymptotes ?

Answer 9

why isn't there a vertical asymptote at x=-1

Answer 10

the numerator ate the factor x+1

Answer 11

\[\large f(x) = \dfrac{x+1}{x^2+x} = \dfrac{x+1}{x(x+1)} = \dfrac{1}{x}~~, x\ne -1\]