If the second derivative is 0, does that mean the function has a point of inflection there?
No. Example: \(\Large\rm \quad y=x, \qquad\qquad y''=0\) This function has no inflection point, yet the second derivative is zero.
Alternatively, if you `set` your second derivative equal to zero, and are able to find an x that corresponds to this, then yes, you have an inflection point. Example: \(\Large\rm \quad y=x^3,\qquad\qquad y''=6x\) Setting our second derivative equal to zero shows us that we have an inflection point at x=0.\[\Large\rm 0=6x, \qquad\qquad 0=x\]
An inflection point occurs when the concavity changes. If the second derivative is zero, it doesn't necessarily imply that it changed signs. The derivative could have went from + to zero to + again. This is not an inflection point, but its 2nd derivative is zero.
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