need a little help:
How would I get an answer for (4x^2-2x+8)-(x^2+3x-2)

Question

need a little help: 
How would I get an answer for (4x^2-2x+8)-(x^2+3x-2)

anonymous · Answer

remove the parentheses using the distributive law (distribute the minus sign) and turn $$(4x^2-2x+8)-(x^2+3x-2)$$ in to $$ 4x^2-2x+8-x^2-3x+2$$

anonymous · Answer

then combine like terms

anonymous · Answer

I'm sorry I don't understand, why would I remove the parentheses?

anonymous · Answer

the question is Subtract the second expression from the first. ( that probably would be important sorry

anonymous · Answer

lets try this problem
suppose you had to do the following arithmetic 
$$35-2\times 12$$ what would you do?

anonymous · Answer

2x12 ?

anonymous · Answer

yes of course
then what?

anonymous · Answer

the point is you have to multiply first, then subtract the whole thing 
same with $$(4x^2-2x+8)-(x^2+3x-2)$$ you have to multiply each term in the second parentheses by $-1$ before you can combine the terms 
that is why step one is to turn it in to $$4x^2-2x+8-x^2-3x+2$$then you can see what the like terms are

anonymous · Answer

I'm sorry I still don't get it but thank you for trying