Question

can someone help me with a calc problem?

Answer 1

if it's continuous at x = 1 => limit from left = limit from right = f(1).

all 3 must be equal to be continuous

Answer 2

\[\lim_{x \rightarrow 1^-}f \left( x \right)=\lim_{x \rightarrow 1^-}3-x=2\]what is f(1)? hint, you need to use the function where x = 1 is in the domain (not the first piece).

Answer 3

you there?

Answer 4

yes sorry my internet keeps on disconnecting me

Answer 5

im plugging in 1 for x?

Answer 6

i dont get what i have to do next

Answer 7

@pgpilot326 ?

Answer 8

yes but in the correct funtion...

Answer 9

for \(\lim_{x \rightarrow 1^+}f \left( x \right)\) you have to use the \(ax^2+bx\) function

Answer 10

and for \(f\left(1\right)\) you have to use that smae function as well.

Answer 11

then you have to check that\[\lim_{x \rightarrow 1^-}f \left( x \right)=\lim_{x \rightarrow 1^+}f \left( x \right)=f \left( 1 \right)\]

Answer 12

you there? did this help?