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(cos^2(x)-sin^2(x))/(sin(x) cos(x)) how to simplify into 2cos2x?
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cos^2x-sin^2x= cos2x
cos^2(x)-sin^2(X)=cos(2x) It's and identity 2sin(x)cos(x)=sin2(x) sin(x)cos(x)=sin(2x)/2 sooo 2cos(2x)/sin(2x)=2cot(2x) I am guessing a wrong answer?
\[\frac{ \cos2x }{ sinxcosx}\]
you r right peter well done buddy
@Auxuris got it ??
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hang on, i'm processing it
ok waitin
but if cos^2(x)-sin^2(X)=cos(2x) then how is 2cos(2x) obtained? is it by flipping the sin(2x)/2 denominator?
if u will flip 2 will come in numerator
so 2 cos2x/sin2x
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so in other words—yes, it is by flipping the sin(2x)/2 denominator.
thank you people :3
welcm :)
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