Mathematics

OpenStudy (anonymous):
Someone please help real quick!!!

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OpenStudy (anonymous):
What the matter?

OpenStudy (anonymous):
Square root quantity of x-98+10=25

OpenStudy (anonymous):
\[\sqrt{x-98}+10=25\]

OpenStudy (anonymous):
take \[10\] the other side (will be negative) then square both sides, then solve for \[x\]

OpenStudy (anonymous):
Solve for x and determine if the solution is extraneous

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OpenStudy (anonymous):
@StudyGurl14 can you help?

OpenStudy (anonymous):
@ilikemath50

OpenStudy (anonymous):
see my answer above

OpenStudy (anonymous):
but how do you determine if its extraneous

OpenStudy (anonymous):
Just solve for \[x\]first then i'll explain what extraneous means

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OpenStudy (anonymous):
-83

OpenStudy (anonymous):
i forgot to square hold on

OpenStudy (anonymous):
27 i think

OpenStudy (anonymous):
wait i forgot 98 was negative

OpenStudy (anonymous):
idk

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OpenStudy (anonymous):
leme get a peice of paper

OpenStudy (anonymous):
\[\sqrt{x-98}=15\]what expression do you get when you square both sides

OpenStudy (anonymous):
x = 623

OpenStudy (anonymous):
323 typo

OpenStudy (anonymous):
yea but if you solve further its x=323

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OpenStudy (anonymous):
yes sorry, but the solution isn't extraneous

OpenStudy (anonymous):
its not?

OpenStudy (anonymous):
how do you tell?

OpenStudy (anonymous):
extraneous means that if you apply the solution to the original equation it won't add up, in this case it adds up perfectly

OpenStudy (anonymous):
oh cool