Mathematics
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OpenStudy (anonymous):
Someone please help real quick!!!
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OpenStudy (anonymous):
What the matter?
OpenStudy (anonymous):
Square root quantity of x-98+10=25
OpenStudy (anonymous):
\[\sqrt{x-98}+10=25\]
OpenStudy (anonymous):
take \[10\] the other side (will be negative) then square both sides, then solve for \[x\]
OpenStudy (anonymous):
Solve for x and determine if the solution is extraneous
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OpenStudy (anonymous):
@StudyGurl14 can you help?
OpenStudy (anonymous):
@ilikemath50
OpenStudy (anonymous):
see my answer above
OpenStudy (anonymous):
but how do you determine if its extraneous
OpenStudy (anonymous):
Just solve for \[x\]first then i'll explain what extraneous means
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OpenStudy (anonymous):
-83
OpenStudy (anonymous):
i forgot to square hold on
OpenStudy (anonymous):
27 i think
OpenStudy (anonymous):
wait i forgot 98 was negative
OpenStudy (anonymous):
idk
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OpenStudy (anonymous):
leme get a peice of paper
OpenStudy (anonymous):
\[\sqrt{x-98}=15\]what expression do you get when you square both sides
OpenStudy (anonymous):
x = 623
OpenStudy (anonymous):
323 typo
OpenStudy (anonymous):
yea but if you solve further its x=323
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OpenStudy (anonymous):
yes sorry, but the solution isn't extraneous
OpenStudy (anonymous):
its not?
OpenStudy (anonymous):
how do you tell?
OpenStudy (anonymous):
extraneous means that if you apply the solution to the original equation it won't add up, in this case it adds up perfectly
OpenStudy (anonymous):
oh cool