Mathematics 37 Online
OpenStudy (anonymous):

OpenStudy (anonymous):

What the matter?

OpenStudy (anonymous):

Square root quantity of x-98+10=25

OpenStudy (anonymous):

$\sqrt{x-98}+10=25$

OpenStudy (anonymous):

take $10$ the other side (will be negative) then square both sides, then solve for $x$

OpenStudy (anonymous):

Solve for x and determine if the solution is extraneous

OpenStudy (anonymous):

@StudyGurl14 can you help?

OpenStudy (anonymous):

@ilikemath50

OpenStudy (anonymous):

OpenStudy (anonymous):

but how do you determine if its extraneous

OpenStudy (anonymous):

Just solve for $x$first then i'll explain what extraneous means

OpenStudy (anonymous):

-83

OpenStudy (anonymous):

i forgot to square hold on

OpenStudy (anonymous):

27 i think

OpenStudy (anonymous):

wait i forgot 98 was negative

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

leme get a peice of paper

OpenStudy (anonymous):

$\sqrt{x-98}=15$what expression do you get when you square both sides

OpenStudy (anonymous):

x = 623

OpenStudy (anonymous):

323 typo

OpenStudy (anonymous):

yea but if you solve further its x=323

OpenStudy (anonymous):

yes sorry, but the solution isn't extraneous

OpenStudy (anonymous):

its not?

OpenStudy (anonymous):

how do you tell?

OpenStudy (anonymous):

extraneous means that if you apply the solution to the original equation it won't add up, in this case it adds up perfectly

OpenStudy (anonymous):

oh cool