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Mathematics
OpenStudy (anonymous):

Someone please help real quick!!!

OpenStudy (anonymous):

What the matter?

OpenStudy (anonymous):

Square root quantity of x-98+10=25

OpenStudy (anonymous):

\[\sqrt{x-98}+10=25\]

OpenStudy (anonymous):

take \[10\] the other side (will be negative) then square both sides, then solve for \[x\]

OpenStudy (anonymous):

Solve for x and determine if the solution is extraneous

OpenStudy (anonymous):

@StudyGurl14 can you help?

OpenStudy (anonymous):

@ilikemath50

OpenStudy (anonymous):

see my answer above

OpenStudy (anonymous):

but how do you determine if its extraneous

OpenStudy (anonymous):

Just solve for \[x\]first then i'll explain what extraneous means

OpenStudy (anonymous):

-83

OpenStudy (anonymous):

i forgot to square hold on

OpenStudy (anonymous):

27 i think

OpenStudy (anonymous):

wait i forgot 98 was negative

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

leme get a peice of paper

OpenStudy (anonymous):

\[\sqrt{x-98}=15\]what expression do you get when you square both sides

OpenStudy (anonymous):

x = 623

OpenStudy (anonymous):

323 typo

OpenStudy (anonymous):

yea but if you solve further its x=323

OpenStudy (anonymous):

yes sorry, but the solution isn't extraneous

OpenStudy (anonymous):

its not?

OpenStudy (anonymous):

how do you tell?

OpenStudy (anonymous):

extraneous means that if you apply the solution to the original equation it won't add up, in this case it adds up perfectly

OpenStudy (anonymous):

oh cool

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