Algebra OpenStudy (anonymous):

Pleaseee help?? Using numerical values, prove the identity. x^3+y^3=(x+y)(x^2-xy+y^2) OpenStudy (bibby):

assign x and y numbers and evaluate OpenStudy (anonymous):

How do I do that? OpenStudy (bibby):

x=2, y=5 etc/ OpenStudy (anonymous):

What are the numbers? Do i pick them myself? OpenStudy (bibby):

I'm pretty sure you get to make them up OpenStudy (anonymous):

Ok hold on. OpenStudy (anonymous):

(2)^3+(3)^3=((2)+(3))((2)^2-(2)(3)+(3)^2) OpenStudy (anonymous):

x=2 and y=3 OpenStudy (bibby):

x^3+y^3=(x+y)(x^2-xy+y^2) x=2//y=3 \[\large (2)^3+(3)^3=(2+3)((2)^2-(2)(3)+(3)^2)\] evaluate the left side now OpenStudy (anonymous):

16+81 OpenStudy (anonymous):

@bibby you there? OpenStudy (bibby):

420 OpenStudy (bibby):

choochin atm OpenStudy (anonymous):

I really need help though :( OpenStudy (bibby):

yeah let me see OpenStudy (bibby):

(x+y)(x^2-xy+y^2) (5)(4-6+9)=(5)(7)=35 OpenStudy (bibby):

whoops OpenStudy (anonymous):

Lol i did the left side which was 16+81 OpenStudy (bibby):

yeah, it doesn't seem to match up. I'll try it with 2 different numbers because wolfram agrees it's true OpenStudy (anonymous):

ok OpenStudy (anonymous):

I mean there is two sides to the problem, so dont you need a letter to bring it over? OpenStudy (bibby):

x^3+y^3=(x+y)(x^2-xy+y^2) x=3, y=4 3^3+4^3=27+64=91 (3+4)(3^2-(3*4)+4^2) 7(9-12+16)=7*13=91 OpenStudy (anonymous): OpenStudy (bibby):

there is no answer. you have to pick out any 2 numbers and prove that both sides evaluate to the same number as I just did OpenStudy (anonymous):

ohhhhhhhhhhhhhhhhhhh!!!!!! OpenStudy (anonymous):

Can i ask you an other question pkease?? OpenStudy (bibby):

I'm married, sorry OpenStudy (anonymous):

oh golly. I mean like math haha OpenStudy (bibby):

rofl I know, post another question and tag me in it. Or post it here, I'm not a cop. the general etiquette is one question per post but i don't care about medals OpenStudy (anonymous):

Ohhhh sowwy! OpenStudy (bibby):

y sowwy just ask yo question OpenStudy (anonymous):

create a polynomial of degree 3 or higher that has three or more terms. @bibby OpenStudy (bibby):

first learn me miss professor lalalala0726 what is the degree of a polynomial OpenStudy (anonymous):

i have no clue:( and reallyneed to get this done in like 10 minutes.. I promise ill learn! OpenStudy (bibby):

timed test? OpenStudy (bibby):

whatever, the degree of a polynomial is the largest exponent. so x^4 + x^3 is of degree 4 OpenStudy (bibby):

so write one out degree 3 or greater with 3 terms or more OpenStudy (anonymous):

Ohhhhok soooo, can i do x^3+x^5? OpenStudy (bibby):

that works. in general we sort downwards so x^5 would cum first then there's the fact that it has to be 3 terms or more and that's 2 OpenStudy (anonymous):

ok, sooo can i do x^5+x^2? OpenStudy (bibby):

that's still 2 terms OpenStudy (anonymous):

then instead of 2 can i do 3? OpenStudy (anonymous):

@bibby OpenStudy (bibby):

you kinda have to do 3 or more, add a term OpenStudy (anonymous):

ok so x^5+x^4 OpenStudy (bibby):

that's still 2 terms OpenStudy (anonymous):

x^5+x^4+x^3 OpenStudy (bibby):

nice OpenStudy (bibby):

correct*

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