Question

find all solutions

2sin^2x+3sinx+1=0

Answer 1

\(\bf 2sin^2(x)+3sin(x)+1=0\implies 2[{\color{brown}{ sin(x)}}]^2+3[{\color{brown}{ sin(x)}}]+1=0\)

notice is just a quadratic equation.... thus factor it and solve for "sin(x)"