Question

HELP WITH CLAC PLEASE

Answer 1

@aum

Answer 2

hmm do you recall what you did on the last one? to find the "a" and "b"

do the same for the left-limit of 1

Answer 3

sorry i put up the wrong question! i got that one

Answer 4

?

Answer 5

nevermind, ill make a new question because it is confusing

Answer 6

well.. .that's very straightforward it seems

Answer 7

i have done 1-4 but which a and b is it asking for? im confused

Answer 8

@aum do you know?

Answer 9

The values for a and b that you found in 4) is to be used in 5).

Answer 10

so for 4 i got -2 and 4, is that right?

Answer 11

a = -2, b = 4 is correct.

Answer 12

im trying to post my work but its not working! one sec

Answer 13

Click on the link and then click on the graph for a bigger image:
http://awesomescreenshot.com/04d3mrh689

Answer 14

can you check my work for 1-4?

Answer 15

@aum

Answer 16

@aum please help me

Answer 17

so that is my graph?

Answer 18

Yeah, that is the graph for Q5.

Q1. Left limit as x-> \(1^-\) is 2.
Right limit as x-> \(1^+\) is 5 when a = 2, b = 3. (not 3 as you have indicated).

Answer 19

I'd answer Q2 as follows:
Left limit as x->\(1^-\) is (3-1) = 2
Right limit as x->\(1^+\) is a(1)^2 + b(1) = a + b
For f(x) to be continuous at x = 1, the left and right limits must be the same.
Therefore, a + b = 2 is the relationship between 'a' and 'b' for f(x) to be continuous at x = 1.

Answer 20

For Q3) I will use the same phrases as in Q2 such as left limit, right limit, etc.

Answer 21

ditto for Q4.

Answer 22

thank you!!