Question

n/3 -3= 12
Please help!

Answer 1

@nincompoop Can you help ??

Answer 2

@mathmath333 ^^

Answer 3

transpose first -3 to the right side of the equation
n/3 = 12 + 3
n/3 = 15
cross multiply to get the value of n

Answer 4

thank you SO much!!!!! @shinalcantara
Can you help me with another one ?

Answer 5

yw :)
ok

Answer 6

6x + 20 = -16

Answer 7

@shinalcantara ^ also, would n= 45 ? for the last question ?

Answer 8

yep

Answer 9

for 6x + 20 - 16
just do the same concept. transpose. then this time since the it's a coefficient, divide. can you do that

Answer 10

hmmm..?

Answer 11

*6x + 20 = -16

Answer 12

transpose 20 to the right..
or let's say subtract 20 on both sides of the equation

Answer 13

6x + 20 - 20 = -16 -20

Answer 14

-4 ?

Answer 15

6x = -36
take note that both are negative
it's like rewriting it as
6x = -16 +(-20)

Answer 16

6x = -36
dividing both sides with 6
x = -6

Answer 17

n/3-3=12
n=45

Answer 18

Okay I have one more....