Question

solve the equation over the interval [0 degrees, 360 degrees]

tan^2theta+5tan theta+3=0

type answer in degrees

Answer 1

\(\large\tt \color{black}{tan^2\theta+5tan\theta+3=0}\)

\(\large \large\tt \color{black}{put~tan\theta=x}\)

\(\large\tt \color{black}{x^2+5x+3=0}\)

Answer 2

thank you. But the answer should be in degrees, solution set. which is why I am so lost :(

Answer 3

u will get value of x in decimals
and by further applying 'arctan' u will get theta in degrees

Answer 4

\(\large \tt \color{black}{\text{use formula for }}\)

\[ax^2+bx+c=0\]

\(\large \tt \color{black}{x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}\)

Answer 5

after getting x just u have to use' arctan' on bothsides