Question

How to solve for y: 4x^8-3x^5*y-3x^3*y-y^2+3x^6=0

Answer 1

@hartnn

Answer 2

\[4x^8-3x^5y-3x^3y-y^2+3x^6=0\]

Answer 3

@zepdrix @ganeshie8 @amistre64 @Destinymasha @radar @waterineyes

Answer 4

\[4x^8-3x^5y-3x^3y-y^2+3x^6=0 \]

Answer 5

How to solve for y??

Answer 6

I am also thinking for that.. :P

Answer 7

I also need experts' advice here.. :)

Nothing more I can help than ( @hartnn @ganeshie8 ) this..!! :P Can we get help here?

Answer 8

zepdrix.. :)

Answer 9

D:

Answer 10

@hartnn

Answer 11

Don't worry, they would be busy, wait for some time, they will surely check it out once.. :)

Answer 12

Wolfram isn't showing any nice factored form.
Are you sure this can be factored? :o

Answer 13

Oh solve for y, my bad :3

Answer 14

\[\Large\rm 4x^8+3x^6-3x^5y-3x^3y-y^2=0\]Multiply everything by -1,
then start grouping some stuff,\[\Large\rm y^2+3x^3(x^2-1)y-x^6(4x^2+1)=0\]And then just throw it into the quadratic formula, yah? :O
That should give you y in terms of x.

Answer 15

So a=1, b=3x^3(x^2-1), c=-x^6(4x^2+1), and I plug these values into the quadratic formula, right?

Answer 16

right.
Just to make sure,
whats the original question ?

Answer 17

I got \[y^2+3x^3(x^2+1)y-x^6(4x^2+3)=0\]

Answer 18

Solve for \(y\):

\[4x^8-3x^5y-3x^3y-y^2+3x^6=0\]

Answer 19

Yes, you are right.. @Idealist10

Answer 20

zepdrix has done some typo or misinterpreting there.. Don't worry, you go ahead.. :) Good..!!

Answer 21

I got it! Thanks!