Question

find domain and range of f(x)=ln(x+sqrt x^2 + 1 )

Answer 1

well with log function the basic domain starting point is

log(x) x> 0

so you need to look at the values of x that make

\[x + \sqrt{x^2 + 1} > 0\]

Answer 2

yea and need answers for this Q and do u know answer?

Answer 3

well it's reasonably straight forward

\[\sqrt{x^2 + 1} > -x\]

squaring any value will make it positive... then adding 1 will always make it larger than -x

so what domain do you think this covers

Answer 4

one method you might consider is graphing the function

https://www.desmos.com/calculator

Answer 5

okay i get answers from website you gave me and thnx