Question

Integrate ((cube root of x) - 1) / square root of x) with respect to x. Do I need to use substitution and what do I substitute?

Answer 1

\[\int{\sqrt[3]x-1\over\sqrt x}dx\]if this is correct, rewrite this with fractional exponents and divide out the terms
you can then integrate straightforward

Answer 2

yes, it's correct. I will try and if I fail, I shall return for help

Answer 3

I'll be around :)

Answer 4

\[6\div5 \times \sqrt[6]{x ^{5}} + 2\sqrt{x}\]
is this the answer, do you maybe know?

Answer 5

sure, just don't forget the +C
*always* include the +C for indefinite integrals

Answer 6

oh yeah, thanks a lot :)

Answer 7

np :)