Question

Factor completely.
125−27y^3

Answer 1

@Compassionate

Answer 2

@Compassionate would the answer be (5-3y)(9y^2+15y+25)??

Answer 3

You should recognize this as "Difference of cubes" given in most textbooks as:
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
:

In our problem you can see 125 = 5^3 and 27 = 3^3, so we have:
:
(5 - 3y)(25 + (5*3y) + 9y^2
which is:
(5 - 3y)(25 + 15y + 9y^2)

Answer 4

thank you!!

Answer 5

wait...compassionateeee....(3wz^3 - 2s) (9w^2z^6 + 6wz^3s + 4s^2) for this equation..6wz^3s what does this mean?? 6wz^3s^3???

Answer 6

@Compassionate