Question

Given the following measurements, A=28, a=19cm, and c=41cm how many triangles are possible?

Answer 1

using law of sines

\[\frac{\sin C}{41} = \frac{\sin 28}{19}\]
\[C = \sin^{-1} (\frac{41 \sin 28}{19})\]
If 41sin28/19 > 1, Then triangle doesn't exist

If 41sin28/19 = 1, Then only 1 triangle exists, a right triangle as C=90

If 41sin28/19 < 1, Then 2 triangles exist, C could have 2 values