Question

I need your help!! Please help me!!!

Answer 1

is that 2 * log... or 2 = log ...?

Answer 2

2 = log

Answer 3

Ok.

So to get rid of the logartim you'll have to raise to a power of 4.
From basic exponetial/logaritmic properties you get
\[a = \log_b(x) \rightarrow b^a = b^{\log_b(x)} = x\]

Answer 4

So would it be 4^2 = 4^log4(10-3x)

Answer 5

Yeah, and the 4^log4 will cancel.

Answer 6

Alright so it would be 16 = 10x-3x. . . . so x would equals 2

Answer 7

Not 10x. You'll just get what's in the original log4 term.

Answer 8

But yeah I think you get the besic idea \[16 = 10-3x \rightarrow 3x = -6 \rightarrow x = -2\]

Answer 9

basic*

Answer 10

Yeah i didnt mean 10 x but alright. Cool thanks. Hey is it ok if you can help me with some other problems.Like send the ones i didnt get.

Answer 11

Sorry, but I was actually about to go offline. The clock is past 1am here and I need to get some rest :P I'll be back tomorrow though!