Question

I need Help!!! Please!!

Answer 1

\(\large \bf -3(5^x)=-51?\)

Answer 2

yes thats the equation

Answer 3

assuming you've already covered logarithms

Answer 4

yeah i have.

Answer 5

\(\bf \large {
-3(5^x)=-51\implies 5^5=\cfrac{\cancel{ -51 }}{\cancel{ -3 }}\implies 5^x=17
\\ \quad \\
{\color{red}{ a}}^y={\color{blue}{ b}}\implies log_{\color{red}{ a}}{\color{blue}{ b}}=y\qquad thus
\\ \quad \\
{\color{red}{ 5}}^x={\color{blue}{ 17}}\implies ?
}\)

Answer 6

hmmm I evn put a 5 up there hhhe lemme fix that quick
\(\large \bf {
-3(5^x)=-51\implies 5^x=\cfrac{\cancel{ -51 }}{\cancel{ -3 }}\implies 5^x=17
\\ \quad \\
{\color{red}{ a}}^y={\color{blue}{ b}}\implies log_{\color{red}{ a}}{\color{blue}{ b}}=y\qquad thus
\\ \quad \\
{\color{red}{ 5}}^x={\color{blue}{ 17}}\implies ?
}\)

Answer 7

x = 1.760

Answer 8

yeap

Answer 9

Thanks!