Question

The graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k:

Answer 1

What is the value of h?

4

2

−2

−4

Answer 2

Can you please help me with this? I'm stuck @jim_thompson5910

Answer 3

Just find new vertex

Answer 4

hint: (h,k) is the vertex of y = a(x-h)^2 + k

because y = a(x-h)^2 + k is referred to as "vertex form"

Answer 5

the value of 'a' determines how the parabola opens and how much it is vertically stretched

Answer 6

so for example, say we have this equation

y = 2(x-4)^2 + 7

this is in the form y = a(x-h)^2 + k where a = 2, h = 4, k = 7

So the parabola opens up ('a' is positive) and it has the vertex (h,k) = (4,7)

Answer 7

that's not the answer as it's just an example

Answer 8

can u help me get the answer? @jim_thompson5910

Answer 9

where is the vertex of that graph?

Answer 10

hk? @jim_thompson5910

Answer 11

forget about h,k for a second

Answer 12

focus on just the visual image you have

Answer 13

what is the vertex?

Answer 14

what do u mean by that? @jim_thompson5910 sorry im confused.

Answer 15

do you know where the vertex is on a parabola? just in general

go ahead and circle the vertex on this drawing

Answer 16

the bottom?

Answer 17

yes the lowest point in this case