Question

fractal-generating function?

Answer 1

f(z)=z^2-2=2i find the first 3 outputs

Answer 2

hmm I'm not exactly 100% sure of what they are asking

Answer 3

and it seems like there are too many equal signs

Answer 4

hmm

Answer 5

is there a typo?

Answer 6

the answers are
A) -2+2i,-2-6i,478-1766i
B) -2+2i,-2-6i,-34+26i
C)-2-6i,-34+26i,478-1766i
D) -2+2i,-2+6i,-34-26i

Answer 7

not sure

Answer 8

Oh im sorry lol its supposed to be f(z)=z^2-2+2i

Answer 9

ok I see what to do

Answer 10

first step is to plug in z = 0

Answer 11

f(0) = ??

Answer 12

k f(0)=0^2-2+2i

Answer 13

simplify as much as possible

Answer 14

ok the first one is -2+2i

Answer 15

so that means we can rule out choice C. Choice C has -2-6i when the first output is -2+2i

Answer 16

ok

Answer 17

we then take this first output, -2+2i, and plug it back into the function


f(z)=z^2-2+2i

f(-2+2i)=(-2+2i)^2-2+2i

f(-2+2i)=???

Answer 18

so then i would have F(-2+2i)=(-2+2i)^2-2+2i

Answer 19

correct

Answer 20

lol beat me to it

Answer 21

you know what you're doing lol

Answer 22

kind of not really lol the fractal one are kicking my bum

Answer 23

16-2+2i

Answer 24

@jim_thompson5910

Answer 25

incorrect

Answer 26

this is the part i got confused on

Answer 27

(-2+2i)^2 = (-2+2i)(-2+2i)

you can use a table like this to help you multiply