Question

how can this be written in parametric form?

Answer 1

any thoughts? we have a point and a direction with any line

Answer 2

sorry I'm confused in this one

Answer 3

first step is just solving for y, put it into slope intercept form.

Answer 4

ok

Answer 5

setiing:

y = mx + b , then let x= 0 + 1t

therefore the parametric version is

x = t
y = mt + b

Answer 6

the direction vector is (1,m) which can be reworked if we dont like fractions

and the anchor point is (0,b)

Answer 7

i got y=5+(3x/2)

Answer 8

good, and let x=t and we have parametricised y in terms of t

Answer 9

thanks i got it :)

Answer 10

i knew you would ;) good luck

Answer 11

x=t and y=5+(3t/2)

Answer 12

or equivalently

x = 0 + 2t
y = 5 + 3t

if you dont like fractions