Question

who can help me with math i have 3 questions left and have to solve in the dark so please help the best you can

Answer 1

@Teddyiswatshecallsme

Answer 2

Post your questions.

Answer 3

ok

Answer 4

@sammixboo

Answer 5

C

Answer 6

Next questions?

Answer 7

midpoint formula : (x1 + x2) / 2 , (y1 + y2)/2

(3,3)....x1 = 3 and y1 = 3
(1,-1)..x2 = 1 and y2 = -1
now we sub
(3 + 1) / 2 , (3 + (-1) / 2
(4/2) , (2/2)
(2,1) is the midpoint ....yep, its C

Answer 8

thx guys thts my nxt 1

Answer 9

distance formula is \(\sqrt{(x_2-x_1)^2+(y_2-y_1)}\)
6, 4 = \(x_1,~y_1\) 2, 3 = \(x_2,~y_2\)

Answer 10

substitute in the values and you have \(\sqrt{2-6)^2+(3-4)^2}\)

Answer 11

Oh! So it's D

Answer 12

sqrt of 7?

Answer 13

whoops should be (2-6)^2

Answer 14

2-6=-4
-4*-4=16
3-4=-1
-1*-1=1
16+1=17
\(\sqrt{17}\)

Answer 15

oh yeah 17 sorry guysim messing up cuz im in the dark

Answer 16

last question tho.....

Answer 17

Mhmm. . .

Answer 18

C

Answer 19

midpoint = \(\dfrac{x_1~+~x_2}{2},~\dfrac{y_1~+~y_2}{2}~6,~4~=~x_1,~y_1~~~2,~3~=~x_2,~y_2\)

Answer 20

thanks Ethereal and sleepyjess :)

Answer 21

Yes, especially Jess. ^^

Answer 22

\(\dfrac{6+2}{2},~\dfrac{4+3}{2}=\dfrac{8}{2},~\dfrac{7}{2}=4,~\dfrac{7}{2}\)