Help!? What is the first step in constructing a perpendicular at a point on a line? a. Place the compass on the end of the line. b. Place the compass on the point. c. Draw an arc from each end of the line. d. Draw a straight line through the point. Find the slope of a line perpendicular to the line containing the points C(–12, 11) and D(3, 9). a. 15 over 2 b. –2 over 15 c. 2 over 15 d. –15 over 2 *Please explain
@DullJackel09 @arabpride @StudyGurl14 @mathmath333 @iGreen
c, for the first one
but technically, to do c, you have to do a...so yea, this is a stupid question
So, which one is it?
first, find the slope of the line going through the points by using the slope formula
(for the second one)
For #2 I got c.
@StudyGurl14
That is incorrect.
Okay. So how do I find the slopes? @StudyGurl14
Slope formula: Where \[(x_1,y_1)\]and \[(x_2,y_2)\]are points on the same line... \[slope=\frac{y_2-y_1}{x_2-x_1}\]
But remember, perpendicular lines have opposite reciprocal slopes
Okay. Before you go, can you help me with one more question?
Sure :)
An irregular quadrilateral has exterior angle measures of 93, 85, and 89. What is the measure of the fourth interior angle? 273 267 93 87 *What is a quadrilateral equal to?
@StudyGurl14
quadrilaterals interior angles add up to 360 degrees
So I got 87.. Am I correct? @StudyGurl14
Yep. great job!
Okay. Can you help me with other questions? I am so confused in Geometry. @StudyGurl14
post new question in new thread and link me :)
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