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Mathematics 14 Online
OpenStudy (anonymous):

Please help I give medal and fan!! Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

OpenStudy (anonymous):

OpenStudy (anonymous):

I really need someone to try to explain it to me in English D: I tried using the lesson and googling but it still seriously does not make any sense.

OpenStudy (freckles):

hey are you still here?

OpenStudy (anonymous):

Yeah Im on XD

OpenStudy (anonymous):

@freckles

OpenStudy (bohotness):

i help you

OpenStudy (anonymous):

Okay that would be great :)

OpenStudy (bohotness):

what you need help with :

OpenStudy (bohotness):

:)

OpenStudy (anonymous):

I need help with how to solve the problem

OpenStudy (anonymous):

With how to "Derive the equation of the parabola with a focus"

OpenStudy (anonymous):

Like, is there a formula or something?

OpenStudy (bohotness):

I don't understand the question

OpenStudy (anonymous):

Me neither D:

OpenStudy (anonymous):

OpenStudy (freckles):

Hey sorry I was having some loading issues.

OpenStudy (freckles):

I kinda like to start by drawing the picture first. Do you know how to do that?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

D;

OpenStudy (freckles):

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1. (0,1) is an ordered pair y=-1 is a line I'm sure you have know trouble graphing those. So let's start by putting those on a graph. |dw:1414702724555:dw|

OpenStudy (freckles):

now the vertex should fall half way in between the focus and the directrix so we actually already know the vertex is what?

OpenStudy (anonymous):

Sorry in a sec open study is loading forever waiting for the graph to show up

OpenStudy (freckles):

|dw:1414702889044:dw| well anyways... you can find the equation by equating the distance between the Focus and a point on the parabola (call it (x,y)) with the distance between the point on the directrix (x,-1) and (x,y)

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