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Mathematics 58 Online
OpenStudy (anonymous):

calc question

OpenStudy (anonymous):

So first I find the critical numbers is that right?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Okay, f ' (x)= -2x+4 0 = -2x + 4 x= 2 (critical number)

OpenStudy (anonymous):

then what ?

OpenStudy (anonymous):

0 and 5 are critical numbers as well.

OpenStudy (anonymous):

So whenever I am given the interval the end and the begging of the interval will be a critical number?

OpenStudy (anonymous):

If it is closed interval.

OpenStudy (anonymous):

Okay:)

OpenStudy (anonymous):

so the critical numbers are 0,2,5.

OpenStudy (anonymous):

What do I do next?

OpenStudy (anonymous):

find the values of \(f(x)\) at the critical numbers.

OpenStudy (anonymous):

Okay, f(0)=-x^2+4x+12=12 f(2)=-x^2+4x+12=16 f(5)=-x^2+4x+12=7

OpenStudy (anonymous):

The critical number that gives highest value for \(f\) will be the maximum

OpenStudy (anonymous):

So, the absolute maximum occurs at x=2, and absolute minimum at x=5 ?

OpenStudy (anonymous):

or just the maximum part of my statement is good?

OpenStudy (anonymous):

Well, the question answers that question.

OpenStudy (anonymous):

the question answers that question? I am sorry, but I don't quite get you-:(

OpenStudy (anonymous):

It asks for both minimum and maximum.

OpenStudy (anonymous):

So I was right, the abs min is 7, and abs max is 16 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

And if i am not confusng the abs max and min is the y-value, not a point or an x-value.

OpenStudy (anonymous):

*confusing

OpenStudy (anonymous):

The max/min will be the output of the function.

OpenStudy (anonymous):

Yes. I was just abt to explain what I meant, but you got me:) Tnx for the help!

OpenStudy (anonymous):

bye

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