Mathematics
26 Online
OpenStudy (anonymous):
calc question
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So first I find the critical numbers is that right?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
Okay,
f ' (x)= -2x+4
0 = -2x + 4
x= 2 (critical number)
OpenStudy (anonymous):
then what ?
OpenStudy (anonymous):
0 and 5 are critical numbers as well.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So whenever I am given the interval the end and the begging of the interval will be a critical number?
OpenStudy (anonymous):
If it is closed interval.
OpenStudy (anonymous):
Okay:)
OpenStudy (anonymous):
so the critical numbers are 0,2,5.
OpenStudy (anonymous):
What do I do next?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
find the values of \(f(x)\) at the critical numbers.
OpenStudy (anonymous):
Okay,
f(0)=-x^2+4x+12=12
f(2)=-x^2+4x+12=16
f(5)=-x^2+4x+12=7
OpenStudy (anonymous):
The critical number that gives highest value for \(f\) will be the maximum
OpenStudy (anonymous):
So, the absolute maximum occurs at x=2, and absolute minimum at x=5 ?
OpenStudy (anonymous):
or just the maximum part of my statement is good?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Well, the question answers that question.
OpenStudy (anonymous):
the question answers that question? I am sorry, but I don't quite get you-:(
OpenStudy (anonymous):
It asks for both minimum and maximum.
OpenStudy (anonymous):
So I was right, the abs min is 7, and abs max is 16 ?
OpenStudy (anonymous):
yes
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
And if i am not confusng the abs max and min is the y-value, not a point or an x-value.
OpenStudy (anonymous):
*confusing
OpenStudy (anonymous):
The max/min will be the output of the function.
OpenStudy (anonymous):
Yes. I was just abt to explain what I meant, but you got me:)
Tnx for the help!
OpenStudy (anonymous):
bye