calc question
So first I find the critical numbers is that right?
Yes.
Okay, f ' (x)= -2x+4 0 = -2x + 4 x= 2 (critical number)
then what ?
0 and 5 are critical numbers as well.
So whenever I am given the interval the end and the begging of the interval will be a critical number?
If it is closed interval.
Okay:)
so the critical numbers are 0,2,5.
What do I do next?
find the values of \(f(x)\) at the critical numbers.
Okay, f(0)=-x^2+4x+12=12 f(2)=-x^2+4x+12=16 f(5)=-x^2+4x+12=7
The critical number that gives highest value for \(f\) will be the maximum
So, the absolute maximum occurs at x=2, and absolute minimum at x=5 ?
or just the maximum part of my statement is good?
Well, the question answers that question.
the question answers that question? I am sorry, but I don't quite get you-:(
It asks for both minimum and maximum.
So I was right, the abs min is 7, and abs max is 16 ?
yes
And if i am not confusng the abs max and min is the y-value, not a point or an x-value.
*confusing
The max/min will be the output of the function.
Yes. I was just abt to explain what I meant, but you got me:) Tnx for the help!
bye
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