Question

Factor each expression completely

Answer 1

\(3(2a-3)^2+17(2a-3)+10\) @TheSmartOne don't I distribute the 3 first to get:
\((6a-9)^2\) first then continue like the previous one?

Answer 2

@kropot72

Answer 3

first expand all terms in brackets
= 12a^2 - 36a + 27 + 341 - 51 + 10

Answer 4

@PRAETORIAN.10

Answer 5

= 12a^2 - 2a - 14
= 2(6a^2 - a - 7)

now factor the trinomial in the brakets

Answer 6

= 2(6a - 7(a + 1)

Answer 7

@ganeshie8

Answer 8

so if that is correct, it will be something like:
\((6a-9)(6a-9)+34a-51+10\) then
\(36a^2-54a-54a+81+34a-51+10\) then I just combine like terms? will this method work? It's what I did last time :/ except I didn't have a number outside the first ()

Answer 9

no - its not (6a - 9(6a - 9)

Answer 10

huh?

Answer 11

3(2a - 3)^2 = 3( 4a^2 - 12a + 9) = 12a^2 - 36a + 27

Answer 12

okay :/ one second

Answer 13

you need to work out the squared part first then multiply by 3

Answer 14

oh! Okay I get it now

Answer 15

good

Answer 16

in my first post it should be 34a not 341

Answer 17

so then I just distribute the 17 then I combine like terms then factor to get (x+_)(x+_)...right?

Answer 18

yes

Answer 19

So I got \(12a^2-2a-14\)

Answer 20

then I will factor? So we can divide it all by 2

Answer 21

right?

Answer 22

ok now you can take 2 out ( the GCF of 12 , 2 and 14)

Answer 23

yes so \(6a^2-x-7\)

Answer 24

= 2(6a^2 - a - 7)

Answer 25

okay but we will only need the 2 at the end, right?

Answer 26

so it'll be 2(x+_)(x+_)

Answer 27

I'm just confused :(

Answer 28

- now you need to factor whats in the parentheses - leave the 2 there

Answer 29

okay so ummmm won't we multiply -7 by 6 and factor that? so -42 and see what adds to -1?

Answer 30

right?