Question

check my work please.
estimate using linearization 1/0.99

Answer 1

i have f(0.99)=1/1-1/(1)^2 * (0.99-1)
ans=1.01

Answer 2

what is the full problem?

Answer 3

it just says estimate the value of 1/0.99 using linearization

Answer 4

oh f(x) = 1/x is your original function

Answer 5

yep

Answer 6

f ' (x) = -1/(x^2)

ok

Answer 7

my f'(x) is -1/x^2

Answer 8

everything looks good because the linearization function L(x) is

L(x) = f(a) + f ' (a)*(x - a)

where a = 1 in this case (since f(1) = 1 is an easy number to compute)

and I'm also getting L(0.99) = 1.01

Answer 9

cool

Answer 10

i got a question though

Answer 11

for example if you have 1/2.99

Answer 12

is your a = 3?

Answer 13

then the old L(x) is a lousy approximation which means you'd have to change to something like a = 3, yes correct

Answer 14

1/x is easy to work with for integer values of x

Answer 15

i see. thanks for your help :D

Answer 16

np