Question

[h o g](x)
h(x)=x^2 + 2x - 1
g(x) = x - 2

Help please?? :/

Answer 1

[h o g ] (x) = h ( x-2 )
now hog means put the value or equation of g into the equation of h on the place of x okay?
so the equation would be
[hog](x)=(x-2)^2 +2x-1
now expand the equation and show me

Answer 2

so then it would be (x-2)^2 + 2(x-2)-1?

Answer 3

or do you only put the g in for the first x?

Answer 4

yeh

Answer 5

then do I distribute?

Answer 6

no sorry my mistake
it would put in all the place of x
[hog] (x)= (x-1)^2 +2(x-2)-1

Answer 7

my mom called me so i forgot that
sorry
that was my mistake

Answer 8

the finally answer is x^2+2x-9, right?

Answer 9

now expand it

Answer 10

but why u put x-1 in the place of x^2 @Haseeb96

Answer 11

(a-b)^2 = a^2 -2ab +b^2
use this formula for that power 2 m

Answer 12

sorry again mistake there would be x-2

Answer 13

[hog](x) = (x-2)^2 +2(x-2) -1

Answer 14

now expand it

Answer 15

no i was confused because i was helping other

Answer 16

I got x^2 - 4 + 2x - 4 - 1 after that and reduced it to x^2 + 2x - 9

Answer 17

right? :P

Answer 18

[hog](x)= (x^2 - 4x + 4) + (2x -4) -1
= x^2 -2x -1
this is correct answer

Answer 19

@rosebird please tag me there