Solve for x. State any restrictions on the variables.

a(bx+2)=cx-12;

A. x=(-12-2a)/(ab-c);ab≠c
B. x=(-12+2a)/(c+ab);ab≠c
C. x=(2a+12)/(c-ab);no restrictions
D. x=(ab-c)/(-12-2a);a≠-1

Question

Solve for x. State any restrictions on the variables.

a(bx+2)=cx-12;

A. x=(-12-2a)/(ab-c);ab≠c  	
B. x=(-12+2a)/(c+ab);ab≠c	
C. x=(2a+12)/(c-ab);no restrictions	
D. x=(ab-c)/(-12-2a);a≠-1

campbell_st · Answer

well distribute on the left side

abx + 2a = cx - 12

collect like terms 

abx - cx = -2a - 12

factor 

x(ab-c) = (-2a -12)

divide both sides by (ab - c)

that will be the solution

campbell_st · Answer

then when you get a solution... have a look at the denominator... and decide if there are restrictions

anonymous · Answer

x=- 2(a+6)/ab-c

_.mufasa._ · Answer

@campbell_st so its A. x -12 -2a$$x=\frac{ -12-2a }{ ab-c } ; ab \neq c $$ ?

campbell_st · Answer

that's correct, the order in the numerator is reversed to what I wrote when I solved it

_.mufasa._ · Answer

@campbell_st  thank you!