Question

2m-1 divided by 4m^3 - 8m^2 + 4m + 6

Answer 1

What would \(2m\) have to be multiplied by to get \(4m^3\)? That is your first term. (Also, are you sure it isn't \(4m^3-8m^2+4m+6\) divided by \(2m-1\)?)

Answer 2

[2m ^{2}-5m….\]

Answer 3

I think the best way to approach this question is to do long division. I just tried it and got a remander of m+6

Answer 4

yeah its a long division problem;; can you show me how you did it?

Answer 5

Step one is to answer the question: "What would \(2m\) have to be multiplied by to get \(4m^3\)?"

Answer 6

i've already gotten as far as 2m^2 - 5m

Answer 7

Okay, so how about 2m into 9m?

Answer 8

Oops 2m-1

Answer 9

We are looking at 2m-1 into -m+6

Answer 10

yes i know I got -m - \[\frac{ 1 }{ 2 }\]

Answer 11

…….