Question

Solve for x.

-ax + 3b > 5

x > the quantity 3 times b minus 5 all over negative a

x > the quantity 5 minus 3 times b all over negative a

x < the quantity 3 times b plus 5 all over negative a

x < the quantity negative 3 times b plus 5 all over negative a

Answer 1

you cannot solve this

Answer 2

\[-ax+3b>5\]
\[-ax>5-3b\] divide by \(-1\) get
\[ax<3b-5\] but you cannot go further

Answer 3

\[x<\frac{ 3b-5 }{ a }\]
Yes you can @satellite73

Answer 4

the reason you cannot divide both sides by \(a\) is because \(a\) is a variable, and could be either positive or negative
if it is positive you leave the inequality alone
if it is negative, you have to switch the inequality
where does this question come from?

Answer 5

@TheSmartOne like hell
you cannot divide an inequality by a variable

Answer 6

Ok.

Answer 7

@luckyjeans please tell me where this question comes from? an idiot math teacher, or an idiot on line system, like FLVS

Answer 8

But 5-3b=-3b+5
right??

Answer 9

oops yes, you are right, they are the same
still want to know the origin of this question

Answer 10

oh and then you divided by -1
nevermind...

Answer 11

same here...

Answer 12

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