Question

write sin(cos-1x-tan-1y) in terms of x and y only where -1 11 years ago

Answer 1

help. me

Answer 2

Recall the identity,
\[\sin(x\pm y)=\sin x\cos y\pm\sin y\cos x\]

Answer 3

This means
\[\sin(\cos^{-1}x-\tan^{-1}y)=\sin(\cos^{-1}x)\cos(\tan^{-1}y)-\sin(\tan^{-1}y)\cos(\cos^{-1}x)\]