Question

Logx/log(x-8) = log6x

Answer 1

\[
\log(A) + \log(B) = \log(A*B) \\
\text{ } \\
\text{If log(C) = log(D), then C = D} \\
\]

Answer 2

\[
\log(x) + \log(x-2) = \log(3x) \\
\log(~x * (x-2)~) = \log(3x) \\
x * (x-2) = 3x \\
x^2 - 2x - 3x = 0 \\
x^2 - 5x = 0 \\
x(x-5) = 0 \\
x = 0 \text{ or } x = 5 \\
\text{Try each solution in the original equation. } \\
\text{x = 0 will not work because log(0) is undefined. } \\
\text{x = 5 will work.} \\
x = 5
\]

Answer 3

ohhhh ok I see now. Thank you

Answer 4

You are welcome.