The position of a particle on the x-axis at time t, t 0, is s(t) = ln(t) with t measured in seconds and s(t) measured in feet. What is the average velocity of the particle for e ≤ t ≤ 2e?

ln2
the quotient of 1 and the quantity of 3 times e
the quotient of the natural logarithm of 2 and e
the quotient of the natural logarithm of 2 and 2

Question

The position of a particle on the x-axis at time t, t > 0, is s(t) = ln(t) with t measured in seconds and s(t) measured in feet. What is the average velocity of the particle for e ≤ t ≤ 2e?

 ln2
 the quotient of 1 and the quantity of 3 times e
 the quotient of the natural logarithm of 2 and e
 the quotient of the natural logarithm of 2 and 2

anonymous · Answer

thank u!!!

anonymous · Answer

@ganeshie8  do you agree that it's b?

ganeshie8 · Answer

"average velocity" is same as "average rate of change"

matlee · Answer

Lol listen to ganeshi

matlee · Answer

im pretty sure he is more certified to say the answer

ganeshie8 · Answer

average velocity between t=2e and t=e :

$$\large \dfrac{\ln(2e) -\ln(e)}{2e-e}$$

simplify

anonymous · Answer

so what do i get as a result? :)
btw ur an awesome helper! :D thank usomuch

ganeshie8 · Answer

saying me awesome wont get u an answer, work on simplifying the above fraction ;p

anonymous · Answer

idk how :(

ganeshie8 · Answer

simplifying denominator should be easy ?

anonymous · Answer

yes e(2-1)

ganeshie8 · Answer

$$\large \dfrac{\ln(2e) -\ln(e)}{2e-e}$$

$$\large \dfrac{\ln(2e) -\ln(e)}{e}$$

ganeshie8 · Answer

use below log property for simplifying numerator :

$$\large \ln (a) - \ln(b) =  \ln(\dfrac{a}{b})$$