Question

Find the verticle asymptotes for y=x+5/x^2-16
A.) none
B.) x=-5
C.) x=-4, x=4
D.) x=0, x=16

Answer 1

A vertical asymptote is created by the restriction on the variable. So you'd do the same thing as when you're finding the discontinuities. :)

1. Factor the denominator.
(x+4)(x-4)
2. Set it equal to 0.
x+4=0 or x-4=0
3. Solve for x.
x=-4 or x=4

Answer 2

Thank You AGain

Answer 3

Lol, no problem. :)