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Mathematics 72 Online
OpenStudy (anonymous):

log(x/5)

jimthompson5910 (jim_thompson5910):

use the rule \[\Large \log\left(\frac{A}{B}\right) = \log(A) - \log(B)\]

jimthompson5910 (jim_thompson5910):

log rules http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

what do i do after i do log(x)-log(5)?

jimthompson5910 (jim_thompson5910):

what are the full instructions

OpenStudy (anonymous):

idk

jimthompson5910 (jim_thompson5910):

it doesn't say it anywhere?

jimthompson5910 (jim_thompson5910):

it just says log(x/5)? nothing else?

OpenStudy (anonymous):

it says "use yhe properties of exponents and logarithms to rewrite each expression in another form."

jimthompson5910 (jim_thompson5910):

ok, so yeah, use that rule to get log(x) - log(5) and you're done

OpenStudy (anonymous):

what rule? help?

jimthompson5910 (jim_thompson5910):

the one I posted at the very top and its given in the link

OpenStudy (anonymous):

it confused me

jimthompson5910 (jim_thompson5910):

what about it confuses you?

OpenStudy (anonymous):

everything

jimthompson5910 (jim_thompson5910):

did you read the article link?

OpenStudy (anonymous):

ya

jimthompson5910 (jim_thompson5910):

the rule is log(A/B) = log(A) - log(B) basically the log of A/B can be broken up into two logs being subtracted: log(A) - log(B)

jimthompson5910 (jim_thompson5910):

example: log(2/3) = log(2) - log(3)

OpenStudy (anonymous):

i did that what do i do next?

jimthompson5910 (jim_thompson5910):

another example: log(7/9) = log(7) - log(9)

jimthompson5910 (jim_thompson5910):

you're done, you just have that one step really

OpenStudy (anonymous):

oh okay

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