Mathematics
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OpenStudy (anonymous):
log(x/5)
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jimthompson5910 (jim_thompson5910):
use the rule
\[\Large \log\left(\frac{A}{B}\right) = \log(A) - \log(B)\]
OpenStudy (anonymous):
what do i do after i do log(x)-log(5)?
jimthompson5910 (jim_thompson5910):
what are the full instructions
OpenStudy (anonymous):
idk
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jimthompson5910 (jim_thompson5910):
it doesn't say it anywhere?
jimthompson5910 (jim_thompson5910):
it just says log(x/5)? nothing else?
OpenStudy (anonymous):
it says "use yhe properties of exponents and logarithms to rewrite each expression in another form."
jimthompson5910 (jim_thompson5910):
ok, so yeah, use that rule to get log(x) - log(5) and you're done
OpenStudy (anonymous):
what rule? help?
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jimthompson5910 (jim_thompson5910):
the one I posted at the very top and its given in the link
OpenStudy (anonymous):
it confused me
jimthompson5910 (jim_thompson5910):
what about it confuses you?
OpenStudy (anonymous):
everything
jimthompson5910 (jim_thompson5910):
did you read the article link?
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OpenStudy (anonymous):
ya
jimthompson5910 (jim_thompson5910):
the rule is log(A/B) = log(A) - log(B)
basically the log of A/B can be broken up into two logs being subtracted: log(A) - log(B)
jimthompson5910 (jim_thompson5910):
example: log(2/3) = log(2) - log(3)
OpenStudy (anonymous):
i did that
what do i do next?
jimthompson5910 (jim_thompson5910):
another example: log(7/9) = log(7) - log(9)
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jimthompson5910 (jim_thompson5910):
you're done, you just have that one step really
OpenStudy (anonymous):
oh okay