Question

Medals. Can someone walk me through how to do this? I really need an expert!!!


A system of equations is shown below:

8x + 5y = 9
3x + 2y = 4

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this.

Part B: Show that the equivalent system has the same solution as the original system of equations.

Answer 1

@amistre64 @thadyoung @undeadknight26

Answer 2

I suck at these things ._.

Answer 3

Darn .:[

Answer 4

Hmmm if you know the solutions to this system you can create ANY system of equations. But we have to follow the rules here.

Answer 5

What are the rules?

Answer 6

"replacing one equation with the sum of that equation and a multiple of the other" you mean?

Answer 7

Yes. I don't understand that statement.

Answer 8

Me neither. One of my relatives is verrry VERY great at math and even she didn't know, so i really feel hopeless with this.

Answer 9

I guess I'll just close this and fail. :/ I never learned this. v-v

Answer 10

@Secret-Ninja

Answer 11

Yes?

Answer 12

I'm pondering.

Answer 13

Okay.

Answer 14

https://answers.yahoo.com/question/index?qid=20140719095908AAMsup4
I found this but its all messed up and I can't make any sense of it. :/

Answer 15

Gotcha!

Answer 16

Thats exactly what I was thinking!

Answer 17

?

Answer 18

example
multiple of \(\Large 7=n(7)\\
where\\n=1,2,3.............\)

just exactly the multiple of any equation
would be

\(\Large n(ax+by)=n(c)\)

Answer 19

Sorry... I still don't get it. o.o

Answer 20

Part (A) is easy if you don't need the answer to be useful. Just follow the steps. Replace the first equation with the sum of it and a multiple of the other equation. Suppose the multiple is -2 (I want to make the numbers smaller, not larger, but either way works.) Then:

8x + 5y = 9 .... original equation
-6x - 4y = -8 .... -2 times each term in the 2nd equation
--------------------
2x + y = 1 .... "sum" of the above, term-by-term on both sides

That leaves you with a new system:

2x + y = 1 .... first equation replaced
3x + 2y = 4 .... 2nd equation unchanged

Answer 21

Thats what the other person said...

Answer 22

example
\(\Large x+2y=3---A\)

\(\Large 2(x+2y)=2(3)\\
\Large 2x+4y=6-----B\)

if we try to put \(\Large x=2\) say then

from \(\Large A\) and \(\Large B\) both u will
get \(\Large y=\dfrac{1}{2}\)

Answer 23

@satellite73 Please help

Answer 24

I know you'll proably totally hate me for this... but I still don't get it. sowwy v-v

Answer 25

I'm just going to write a bunch or rubbish.... Even if I get this wrong I'll get a B on the test.

Answer 26

*of

Answer 27

Okay..