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OpenStudy (anonymous):
Can someone please confirm if I'm starting this problem right? Find the lines that are (a) tangent and (b) normal to the curve at the given point 6x^2 +3xy + 2y^2 + 17y - 6 = 0, (1, 0 ) 12x + 3xy' + 4y' + 17 = 0 (1,0) 3xy'+4y' = 17 - 12x y'( 3x + 4) = 17 - 12x y' = 17 - 12x/3x + 4
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